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0.00218x^2+25.8814x-78863.98=0
a = 0.00218; b = 25.8814; c = -78863.98;
Δ = b2-4ac
Δ = 25.88142-4·0.00218·(-78863.98)
Δ = 1357.54077156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25.8814)-\sqrt{1357.54077156}}{2*0.00218}=\frac{-25.8814-\sqrt{1357.54077156}}{0.00436} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25.8814)+\sqrt{1357.54077156}}{2*0.00218}=\frac{-25.8814+\sqrt{1357.54077156}}{0.00436} $
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